WebIf the team believes that there are only 10 players that have a chance of being chosen in the top 5, how many different orders could the top 5 be chosen? For this problem we are finding an ordered subset of 5 players (r) … WebEvery addition of a character multiplies the number of possibilities by 4. For instance, if you have N possibilities of passwords, and I now add another letter, then for any seuqence [ x y z... w] you can now generate four times: [ x y z... w a], [ x y z... w b], [ x y z... w c], [ x y z... w …
Combinations Calculator (nCr)
WebMath Algebra A certain lock has four tumblers, and each tumbler can assume five positions. How many different possibilities are there? A certain lock has four tumblers, and each tumbler can assume five positions. How many different possibilities are there? Question A certain lock has four tumblers, and each tumbler can assume five positions. WebFeb 24, 2024 · Solution: There are two possibilities, the first letter is a vowel or the first letter is a consonant. If the first letter is a vowel we have three choices, followed by five for a consonant, two for a second vowel, four for a second consonant, one for the last vowel and three for the last consonant. theoret funeral
A state makes license plates with five letters followed by ... - Brainly
WebPut the rule on its own line: Example: the "has" rule a,b,c,d,e,f,g has 2,a,b Combinations of a,b,c,d,e,f,g that have at least 2 of a,b or c Rules In Detail The "has" Rule The word "has" followed by a space and a number. Then a comma and a list of items separated by … WebHow many possible meals are there? The answer is calculated by multiplying the numbers to get 3 x 6 x 4 = 72. You can think of it as first there is a choice among 3 soups. Then, for each of these choices there is a choice among 6 entrées resulting in 3 x 6 = 18 possibilities. WebFeb 13, 2024 · Take a look; there is only one way you can obtain 2: 1+1, but for 4, there are three different possibilities: 1+3, 2+2, 3+1, and for 12 there is, once again, only one variant: 6+6. It turns out that 7 is the most likely result with six possibilities: 1+6, 2+5, 3+4, 4+3, 5+2, and 6+1. The number of permutations with repetitions in this set is 36. theorethical principla to support teaching